purplefish53
Answered

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How many moles are present in 93 grams of potassium carbonate

Sagot :

rubabzehra9127

Answer:

○[tex]No. Of Moles = \frac{mass of the substance}{atomic mass of the substance} \\[/tex]

No of moles = 93 g ÷ 138 amu

No of moles = 0.67 moles

93 grams of potassium carbonate contain 0.67 moles.

samueladesida43

There are 0.67 moles present in 93 grams of potassium carbonate (K2CO3). Details about no of moles can be found below.

How to calculate number of moles?

The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass.

According to this question, there are 93 grams of potassium carbonate.

Molar mass of K2CO3 = 138.205 g/mol

No of moles = 93g ÷ 138.205g/mol = 0.673mol

Therefore, there are 0.67 moles present in 93 grams of potassium carbonate (K2CO3).

Learn more about number of moles at: https://brainly.com/question/26416088

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