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Sagot :
Answer:
○[tex]No. Of Moles = \frac{mass of the substance}{atomic mass of the substance} \\[/tex]
No of moles = 93 g ÷ 138 amu
No of moles = 0.67 moles
93 grams of potassium carbonate contain 0.67 moles.
There are 0.67 moles present in 93 grams of potassium carbonate (K2CO3). Details about no of moles can be found below.
How to calculate number of moles?
The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass.
According to this question, there are 93 grams of potassium carbonate.
Molar mass of K2CO3 = 138.205 g/mol
No of moles = 93g ÷ 138.205g/mol = 0.673mol
Therefore, there are 0.67 moles present in 93 grams of potassium carbonate (K2CO3).
Learn more about number of moles at: https://brainly.com/question/26416088
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