Answer:
d; x≥-3 and x≤-7
Step-by-step explanation:
absolute value always has two 'values', one positive and one negative
for example, |4| = 4 and -4
so for this problem, |x + 5| ≥ 2 we can find the positive values by just solving as normal: x + 5 ≥ 2, so x ≥ -3
now we must find the values when the inequality is negative:
-|x + 5| ≥ 2
distribute the negative:
-x - 5 ≥ 2
-x ≥ 7
divide by -1 and remember to reverse the inequality symbol to get:
x ≤ -7
so the solutions exist at -3 and greater, as well as at -7 and less
