Answered

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Solve the following quadratic function by using the quadratic formula: x^2 +
2x - 1 = 2 *


Sagot :

Answer:

x = 1 or x = -3

Step-by-step explanation:

[tex]ax^{2}[/tex] + bx + c = 0

x = [tex]\frac{-b±\sqrt{b^{2}-4ac } }{2a\\}[/tex]

as [tex]x^{2}[/tex] + 2x - 1 = 2 ⇔  [tex]x^{2}[/tex] + 2x - 3 = 0, its solution is

x = [tex]\frac{-2±\sqrt{2^{2}-4 *1*(-3)} }{2*1}[/tex]

=  [tex]\frac{-2±\sqrt{4+12} }{2}[/tex] =  [tex]\frac{-2±\sqrt{16} }{2}[/tex] =  [tex]\frac{-2±\ 4 }{2}[/tex]

therefore, x = 1 or x = -3

hope this helps! :D

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