Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

determine the value of x to the nearest thousandth in the equation 8(2)^x+3=48

Sagot :

LammettHash

You probably mean either

[tex]8\cdot2^x + 3 = 48[/tex]

or

[tex]8\cdot2^{x+3} = 48[/tex]

Write 8 = 2³, so that in the first interpretation,

[tex]8\cdot2^x = 2^3 \cdot 2^x = 2^{x + 3}[/tex]

and in the second,

[tex]8\cdot2^{x+3} = 2^3 \cdot 2^{x+3} = 2^{x + 6}[/tex]

Then in the first interpretation, we have

[tex]2^{x + 3} + 3 = 48 \implies 2^{x + 3} = 45 \implies x + 3 = \log_2(45) \implies x = \log_2(45) - 3 \approx \boxed{2.492}[/tex]

Otherwise, the second interpretation gives

[tex]2^{x + 6} = 48 \implies x + 6 = \log_2(48) \implies x = \log_2(48) - 6 \approx -0.415[/tex]

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.