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Sagot :
The true claim about mechanical energy dissipated due to friction on each block is [tex]W_2 = W_4 \ > \ W_3[/tex].
The given parameters:
- Velocity at time 0, v₀ = 2v₀
- Velocity at time interval 1, v₁ = 3v₀
- Velocity at time interval 2, v₂ = 3v₀
- Velocity at time interval 3, v₃ = 2v₀
- Velocity at time interval 4, v₄ = 2v₀
The change in kinetic energy of the blocks is equal to the mechanical energy dissipated.
[tex]W = \Delta K.E= \frac{1}{2}(v_2^2 - v_1^2) \\\\W_2 = \frac{1}{2} m(3v_0^2- 3v_0^2) = 0\\\\W_3 = \frac{1}{2} m((2v_0)^2 - (3v_0)^2) = -2.5 mv_0^2 \\\\W_4 = \frac{1}{2}m( 2v_0^2 - 2v_0^2) = 0[/tex]
Thus, we can conclude the following for the mechanical energy dissipated due to friction on each block;
[tex]W_2 = W_4 \ > \ W_3[/tex].
Learn more about energy lost to friction here: https://brainly.com/question/12315903
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