cqmcginness
Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

9. The probability of a child being born with light-colored eyes to two particular parents is 0.25.
The parents intend to have 5 children. Find the variance of this binomial distribution.
0.9
1.0
1.3
3.8

Sagot :

LammettHash

If X is a random variable representing the number of children that end up having light-colored eyes, then X follows a binomial distribution with success probability p = 0.25 and number of trials n = 5.

The variance of a binomial distribution with these parameters is n p (1 - p), so the variance in this case would be

5 • 0.25 • (1 - 0.25) = 0.9375 ≈ 0.9

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.