Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A student hangs a slinky over the edge of a stairwell. The slinky is stretched so that it is just above the ground. The student sends a pulse down the slinking and measures the speed to be 18m/s. The student then vibrates the slinky with a frequency of 4.5 Hz and notices that 4 nodes produced. The end near the floor is an open end and the end where the student his holding the slinking is a fixed end.] How high is the stairwell?
a) Calculate the wavelength of the slinky. (4.0 m)
b) Draw a well labelled diagram of the situation. (because of one open end, there are 3.5 loops)
c) Calculate the height of the stairwell. (h = 7 wavelength quarters, 7/4λ = h, h = 7.0 m)


Sagot :

The drawing of the wave in the slinky shows the node and antinode

in the form of a standing wave pattern.

The correct responses;

  • a) 4.0 meters
  • b) Please find attached the drawing of the wave motion in the slinky
  • c) 7.0 m

Method used to arrive at the response above:

Given parameters;

The speed of the wave pulse through the slinky, v = 18 m/s

The frequency with which the student vibrates the slinky, f = 4.5 Hz

Number of nodes in the slinky, n = 4 nodes

a) Wavelength of the slinky λ:

The wavelength of the slinky, λ, is given as follows;

[tex]\displaystyle \lambda = \mathbf{ \frac{v}{f}}[/tex]

Therefore;

[tex]\displaystyle \lambda = \frac{18 \, m/s }{4.5 \, Hz} = \mathbf{4.0 \, m}[/tex]

  • The wavelength of the wave formed on the slinky, λ = 4.0 meters

b) Drawing of a well labelled diagram of the situation:

The attached drawing of the situation shows the wavelength of the

wave equal to the distance between three consecutive nodes, N

The number of loops = 3 complete loops + Half of a loop = 3.5 loops

c) To calculate for the height of the stairwell:

The length of the wavelength, λ = Length of two complete loops

Height of the stairwell = 3.5 loops

2 loops = λ

Therefore;

[tex]\displaystyle Height \ of \ stairwell = \frac{\lambda}{2 } \times 3.5 = \mathbf{1.75 \cdot \lambda}[/tex]

Which gives;

  • Height of the stairwell, h = 1.75 × 4.0 m = 7.0 m

Learn more about wave motion here:

https://brainly.com/question/296307

View image oeerivona
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.