angelyehia61383
Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

please help me i'll mark as brainliest​

Please Help Me Ill Mark As Brainliest class=

Sagot :

Answer:   a = 0

Step-by-step explanation:

ok we got [tex]f(x) = x^2 + ax + 3[/tex]. Our task is to choose a value for [tex]a[/tex] so that "the tangent line to [tex]f[/tex] at [tex]x = 2[/tex] passes through [tex](1, 3)[/tex]."

Well [tex]f(2) = 4 + 2a + 3 = 2a + 7[/tex], and [tex]f'(2) = 2(2) + a = 4 + a[/tex]. So our tangent line looks like this:

[tex]y - 3 = (4 + a)(x - 1)[/tex]

[tex]y = 4x + ax - a - 1[/tex]

We know this must contain the point [tex](2, 2a + 7)[/tex], so

[tex]2a + 7 = 4(2) + a(2) - a - 1[/tex]

[tex]a = 8 - 7 - 1\\\\\boxed{a = 0}[/tex]

becca6673913
Just had this on my test! A=0 is 100% correct!
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.