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What is the vertex of y=3x^2 - 6x + 12?

Sagot :

sqdancefan

Answer:

  (1, 9)

Step-by-step explanation:

For quadratic ax^2 +bx +c, the vertex is located at ...

  x = -b/(2a)

For your quadratic, this is ...

  x = -(-6)/(2(3)) = 1

The y-value at that point is ...

  y = 3(1^2) -6(1) +12 = 3 -6 +12 = 9

The vertex is (x, y) = (1, 9).

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