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All points of the step function f(x) are graphed.

On a coordinate plane, a step graph has horizontal segments that are each 2 units long. The left end of each segment is an open circle. The right end of each segment is a closed circle. The left-most segment goes from (negative 4, 1) to (negative 2, 1). Each segment is 1 unit higher and 2 units farther to the right than the previous segment. The right-most segment goes from (2, 4) to (4, 4).
What is the domain of f(x)?

{x| –4 < x ≤ 4}
{x| –3 < x ≤ 4}
{x| 1 < x ≤ 4}
{x| 2 < x ≤ 4}

Sagot :

sqdancefan

Answer:

  (a)  {x| –4 < x ≤ 4}

Step-by-step explanation:

The domain is the horizontal extent of the graph.

Your problem statement tells you the left end is an open circle at x=-4, and the right end is a closed circle at x=4. The domain is ...

  -4 < x ≤ 4

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