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the multiplicative inverse of 1/4 and 5t-1/4

Sagot :

zoraisntcute

Answer:

[tex]\frac{16t}{5} and \frac{1}{5}[/tex]

Step-by-step explanation:

[tex]\frac{1}{4}*\frac{5t-1}{4}=\frac{5t-1}{16}[/tex]

Inverse of [tex]\frac{5t-1}{16}[/tex] = [tex]\frac{16t}{5}+\frac{1}{5}[/tex]

Please leave a comment if I got anything wrong.

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