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does anyone know to do how do this 6x^0y^8-(2y^2)^4?

Sagot :

Answer:

4y⁸

Step-by-step explanation:

6x⁰y⁸-(2y²)⁴

x⁰=1 and

power product rule for (2y²)⁴ = 2y²ˣ⁴ = 2y⁸

6y⁸- 2y⁸

4y⁸

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