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Solve Linear Equations with Rational Numbers #2

Solve Linear Equations With Rational Numbers 2 class=

Sagot :

Answer:

  multiply by 3, applying the multiplication property of equality

  -6/5x = 4y +6

Step-by-step explanation:

Your video probably tells you what is expected here.

Ordinarily, we would multiply both sides of the equation by the least common denominator of the fraction: 15. That would eliminate all of the fractions. Your form seems to indicate that the coefficient of x remains a fraction after the multiplication. That makes the intent unclear to those of us who have not seen your video.

The multiplication property of equality is applied.

1.

Multiply both sides of the equation by 15. This clears all the fractions.

  [tex]15(-\dfrac{2}{5}x)=15(\dfrac{4}{3}y+2)\\\\-6x=20y+30[/tex]

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2.

If we just clear the fraction for y, we do that by multiplying both sides by 3.

  [tex]3(-\dfrac{2}{5}x)=3(\dfrac{4}{3}y+2)\\\\\dfrac{-6}{5}x=4y+6[/tex]