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A sample containing 6.5 moles of NH 3 is reacted with excess CuO. How many moles

of each product can be made?
N2=
Cu=
H20=

Sagot :

sebassandin

This problem is providing information about the moles of ammonia that are consumed in excess copper(II) oxide and the produced moles of nitrogen, copper and water are required.

Chemical equation:

At first instance, we must write the balanced chemical reaction that takes place when the aforementioned reactants are reacted, in agreement to the law of conservation of mass:

[tex]2NH_3+3CuO\rightarrow N_2+3Cu+3H_2O[/tex]

Mole ratios:

Next, since 6.5 moles of ammonia, NH3, is given, it turns out possible for us to apply the following mole ratios in order to calculate the required moles of each product:

[tex]6.5molNH_3*\frac{1molN_2}{2molNH_3} =3.25molN_2\\\\6.5molNH_3*\frac{3molCu}{2molNH_3} =9.75molCu\\\\6.5molNH_3*\frac{3molH_2O}{2molNH_3} =9.75molH_2O[/tex]

Learn more about mole ratios: https://brainly.com/question/15288923

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