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A sample containing 6.5 moles of NH 3 is reacted with excess CuO. How many moles

of each product can be made?
N2=
Cu=
H20=


Sagot :

This problem is providing information about the moles of ammonia that are consumed in excess copper(II) oxide and the produced moles of nitrogen, copper and water are required.

Chemical equation:

At first instance, we must write the balanced chemical reaction that takes place when the aforementioned reactants are reacted, in agreement to the law of conservation of mass:

[tex]2NH_3+3CuO\rightarrow N_2+3Cu+3H_2O[/tex]

Mole ratios:

Next, since 6.5 moles of ammonia, NH3, is given, it turns out possible for us to apply the following mole ratios in order to calculate the required moles of each product:

[tex]6.5molNH_3*\frac{1molN_2}{2molNH_3} =3.25molN_2\\\\6.5molNH_3*\frac{3molCu}{2molNH_3} =9.75molCu\\\\6.5molNH_3*\frac{3molH_2O}{2molNH_3} =9.75molH_2O[/tex]

Learn more about mole ratios: https://brainly.com/question/15288923