theamazingkingnoob
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How many solutions does this equation have 9y + 5 = 3y + 1 + 6y + 4

Sagot :

a1a1a1a17

Answer:

9y+5=3y+1+6y+4=>

-9y+3y+6y=5-1-4=>

0=0

Amphitrite1040

Hey there!

9y + 5 = 3y + 1 + 6y + 4

9y + 5 = 9y + 5

SUBTRACT 9y to BOTH SIDES

9y + 5 - 9y = 9y + 5 - 9y

SIMPLIFY IT!

NEW EQUATION: 5 = 5

SUBTRACT 5 to BOTH SIDES

5 - 5 = 5 - 5

0 = 0

Therefore, your answer is:

All real numbers

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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