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Find 3 consecutive POSTIVE odd numbers such that two times the first number plus the second number is one more than twice the third number. What is the THIRD number?

Sagot :

Using a system of equations, it is found that the third number is 11.

System of equations:

  • The variables representing the numbers are: x, y and z.
  • They are consecutive odd numbers, that is, they are separated by 2, hence:

[tex]y = x + 2[/tex]

[tex]z = y + 2 = x + 4[/tex]

Two times the first number plus the second number is one more than twice the third number, hence:

[tex]2x + y = 1 + 2z[/tex]

Then, considering the equations we have for y and z as functions of x:

[tex]2x + x + 2 = 1 + 2(x + 4)[/tex]

[tex]3x + 2 = 2x + 9[/tex]

[tex]x = 7[/tex]

Hence, the third number is:

[tex]z = x + 4 = 7 + 4 = 11[/tex]

To learn more about system of equations, you can take a look at https://brainly.com/question/14183076

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