Answered

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Find the solution of the system of equations.
10x+10y=40
5x+3y=8

Sagot :

Nonportrit

Answer:

x = -2 & y = 6

Step-by-step explanation:

[tex]10x+10y=40[/tex]

[tex]10x+10y+ -10y=40+-10y[/tex]

[tex]10x=-10y+40[/tex]

[tex]\frac{10x}{10} =\frac{-10y+40}{10}[/tex]

[tex]x=-y+4[/tex]

[tex]5x+3y=8[/tex]

[tex]5(-y+4)+3y=8[/tex]

[tex]-2y+20=8[/tex]

[tex]-2y+20+-20=8+-20[/tex]

[tex]-2y=-12[/tex]

[tex]\div2[/tex]

[tex]y=6[/tex]

[tex]x=-y+4[/tex]

[tex]x=-6+4[/tex]

[tex]x=-2[/tex]

Hope this helps.

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