Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Answer:
[tex]\sf{ \bar{BC}} = \sf{ \bar{EC}}[/tex]
Explaination:
[tex]\sf \angle EBC = 40 \degree \: ..(given) \\\sf \angle EBC + \angle \: CEB + \angle BCE = 180 \degree \\ \sf 40 + \angle \: CEB + 100 = 180 \: \\ \sf ..(sum \: of \: measure \: of \: all \: angles \: of \: triangle \\ \sf \angle \: CEB + 140 = 180 \\\angle \: \sf \: CEB = 180 - 140 \\ \sf \: \angle \: CEB = 40 \degree \\ \\ \sf \therefore \: \angle EBC = \angle \: CEB \\ \sf \: In \:triangle \: sides \: opposite \: to \: congruent \: angles \: are \: congruent \\ \therefore \: \sf{ \bar{BC}} = \sf{ \bar{EC}}[/tex]
[tex] \sf \pink{hope \: it \: helps :)}[/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.