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A skydiver drops himself from a plane, he passes 100 m before opening a parachute. If he experiences free fall motion, how much is his final speed at that point?.

Sagot :

The equations of motion can be used to obtain the velocity as 44.7 m/s.

How are the equations of motion used?

The equations of motion are used to solve questions that bother on kinematics. In this case, we are dealing with motion under gravity. In order to find the final velocity, we have to use the equation;

v^2 = u^2 + 2gh

  • v = final velocity
  • u = initial velocity
  • g = acceleration due to gravity
  • h = height

Since he dropped from a height, u = 0 m/s

v^2 = 0^2 + 2 (10) (100)

v^2 = 2000

v = √2000

v = 44.7 m/s

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