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Sagot :
Answer:
2.25 (or [tex]\frac{9}{4}[/tex]) g/mL
Skills needed: Density
Step-by-step explanation:
1) Briefly, let's cover what density is:
- It is [tex]\frac{mass}{volume}[/tex]
- Measures the mass per unit of volume
- In this situation the formula for density is: [tex]\frac{m_f-m_i}{v_f-v_i}[/tex]
---> [tex]m_f[/tex] is the final mass
---> [tex]m_i[/tex] is the initial mass
---> [tex]v_f[/tex] is the final volume
---> [tex]v_i[/tex] is the initial volume
2) In this case, we start out with a mass of 180 grams as stated in the problem, and also 50 mL of water initially.
This means that:
- [tex]m_i[/tex] is 180 g
- [tex]v_i[/tex] is 50 mL
3) Also, we end up with 270 g in mass, and 90 mL of water finally.
- [tex]m_f[/tex] is 270g
- [tex]v_f[/tex] is 90 mL
4) We can find density by substitute given the values above:
[tex]\frac{270-180}{90-50} = \frac{90}{40} = \frac{9}{4} \text{ or } 2.25[/tex]
5) Our answer is 2.25 g/mL (since mass is grams (g), and volume is milliliters (mL) in the problem above).
- ∆V=90-50=40mL
- ∆m=270-180=90g
Density be [tex]\rho[/tex]
[tex]\\ \sf\longmapsto \rho=\dfrac{m}{v}[/tex]
[tex]\\ \sf\longmapsto \rho=\dfrac{90}{40}[/tex]
[tex]\\ \sf\longmapsto \rho=\dfrac{9}{4}[/tex]
[tex]\\ \sf\longmapsto \rho=2.2g/ml[/tex]
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