Answer:
See below
Step-by-step explanation:
Recall that [tex]\overrightarrow{v}=\langle ||\overrightarrow{v}||cos\theta,||\overrightarrow{v}||sin\theta\rangle[/tex] for a vector [tex]\overrightarrow{v}[/tex] with magnitude [tex]||v||[/tex] that makes an angle [tex]\theta[/tex] with the positive x-axis.
Thus, the component form of vector [tex]\overrightarrow{v}[/tex] is [tex]\overrightarrow{v}=\langle5cos(143.13^\circ),5sin(143.13^\circ)\rangle=\langle-4,3\rangle[/tex]
Therefore:
[tex]u=\langle2,5\rangle[/tex]
[tex]v=\langle-4,3\rangle[/tex]
[tex]u+v=\langle2,5\rangle+\langle-4,3\rangle=\langle2+(-4),5+3\rangle=\langle-2,8\rangle[/tex]
[tex]2u=2\langle2,5\rangle=\langle2(2),2(5)\rangle=\langle4,10\rangle[/tex]
[tex]-3v=-3\langle-4,3\rangle=\langle-3(-4),-3(3)\rangle=\langle12,-9\rangle[/tex]
View the attached graph to see each vector graphed
