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Sagot :
The mass of hydrogen atoms in the sample of water is 3.98g
This can be solved by understanding of Avogadro's number and mole relationship concept.
Avogadro's number
This is a proportionality that relates the number of particles to the amount of substance in that sample and it is given as [tex]6.02*10^2^3[/tex]
A molecule of water have the chemical formula as H[tex]_2[/tex]O. This implies that for every 1 atom or molecule of oxygen, 2 hydrogen must be present.
In the question given, we have [tex]12*10^2^3[/tex] atoms of oxygen. This implies we must have [tex]2*(12*10^2^3)=2.4*10^2^4[/tex]
Now, let's compare this molar mass - Avogadro's number
molar mass of hydrogen = 1g/mol
[tex]1g/mol=6.023*10^2^3particles\\xg=2.4*10^2^4particles\\x=\frac{1*2.4*10^2^4}{6.023*10^2^3}\\x=3.98g[/tex]
From the calculation above, we would have 3.98g of hydrogen present in that particles of oxygen.
learn more on Avogadro's concept
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