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Sagot :
We are given –
- Height (h) of cone is = 19.9cm
- Radius (r) of cone is = 9.6 cm
According to the question, we are asked to find out volume of the cone. As we know –
- Volume of cone = ⅓ πr²h
Substituting values –
[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf Volume_{(Cone)} = \dfrac{1}{3} π r^2h}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf Volume_{(Cone)} = \dfrac{1}{3} π\times (9.6)² \times 19.9[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf Volume_{(Cone)} = \dfrac{1}{3} π \times 92.16 \times 19. 9[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf Volume_{(Cone)} = 96.4608 \times 19.9[/tex]
[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf Volume_{(Cone)} = 1919.57\:cm³}\\[/tex]
[tex]\therefore{\underline{\textsf{ Volume of cone is \textbf{1919.57cm³}}}} [/tex]
Know More –
- C.S.A of cone = πrl
- T.S.A of cone = πrl + πr²
- Volume of cuboid = l × b × h
- C.S.A of cuboid = 2(l + b)h
- T.S.A of cuboid = 2(lb + bh + lh)
- C.S.A of cube = 4a²
- T.S.A of cube = 6a²
- Volume of cube = a³
- Volume of sphere = 4/3πr³
- Surface area of sphere = 4πr²
- Volume of hemisphere = ⅔ πr³
- C.S.A of hemisphere = 2πr²
- T.S.A of hemisphere = 3πr²
_________________________________________
Step-by-step explanation:
Volume of cone = 1/3πr²h
here,
- Height = 19.9 cm
- base radius = 9.6cm
Putting the known values ,
Volume = [tex] \frac{1}{3} \times 3.14 \times 9.6 {}^{2} \times 19.9cm {}^{3} [/tex]
Volume = 1919.56 cm³
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