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Find the volume of a right circular cone that has a height of 19.9 cm and a base with a radius of 9.6

Sagot :

We are given –

  • Height (h) of cone is = 19.9cm
  • Radius (r) of cone is = 9.6 cm

According to the question, we are asked to find out volume of the cone. As we know –

  • Volume of cone = ⅓ πr²h

Substituting values –

[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf Volume_{(Cone)} = \dfrac{1}{3} π r^2h}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf Volume_{(Cone)} = \dfrac{1}{3} π\times (9.6)² \times 19.9[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf Volume_{(Cone)} = \dfrac{1}{3} π \times 92.16 \times 19. 9[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf Volume_{(Cone)} = 96.4608 \times 19.9[/tex]

[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf Volume_{(Cone)} = 1919.57\:cm³}\\[/tex]

[tex]\therefore{\underline{\textsf{ Volume of cone is \textbf{1919.57cm³}}}} [/tex]

Know More –

  • C.S.A of cone = πrl
  • T.S.A of cone = πrl + πr²
  • Volume of cuboid = l × b × h
  • C.S.A of cuboid = 2(l + b)h
  • T.S.A of cuboid = 2(lb + bh + lh)
  • C.S.A of cube = 4a²
  • T.S.A of cube = 6a²
  • Volume of cube = a³
  • Volume of sphere = 4/3πr³
  • Surface area of sphere = 4πr²
  • Volume of hemisphere = ⅔ πr³
  • C.S.A of hemisphere = 2πr²
  • T.S.A of hemisphere = 3πr²

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SupremeStrange

Step-by-step explanation:

Volume of cone = 1/3πr²h

here,

  • Height = 19.9 cm
  • base radius = 9.6cm

Putting the known values ,

Volume = [tex] \frac{1}{3} \times 3.14 \times 9.6 {}^{2} \times 19.9cm {}^{3} [/tex]

Volume = 1919.56 cm³

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