mholmes2007
Answered

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LAST ATTEMPT! MARKING AS BRAINLIEST!! )

LAST ATTEMPT MARKING AS BRAINLIEST class=

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\huge \bf༆ Answer ༄[/tex]

Let's solve ~

Zero :

[tex]\qquad \looparrowright \sf(5 - 5) + (5 - 5) = 0[/tex]

One :

[tex]\qquad \looparrowright \sf \dfrac{5 + 5}{5 + 5} = 1[/tex]

Two :

[tex]\qquad \looparrowright \sf \dfrac{5}{5} + \dfrac{5}{5} = 2[/tex]

Three :

[tex]\qquad \looparrowright \sf \dfrac{5 + 5 + 5}{5} = 3[/tex]

Four :

[tex]\qquad \looparrowright \sf \dfrac{(5 \times 5) - 5}{5} = 4[/tex]

Five :

[tex]\qquad \looparrowright \sf \dfrac{ {5} - {5} }{5} + 5 = 5[/tex]

Six :

[tex]\qquad \looparrowright \sf \dfrac{(5 \times 5) + 5}{5} = 6[/tex]

Seven :

[tex]\qquad \looparrowright \sf \dfrac{5 + 5}{5} + 5 = 7[/tex]

Eight :

[tex]\qquad \looparrowright \sf(.5 \times 5) + 5 + .5 = 8[/tex]

Nine :

[tex]\qquad \looparrowright \sf5 + 5 - \dfrac{5}{5} = 9[/tex]

Ten :

[tex]\qquad \looparrowright \sf \dfrac{55 - 5}{5} = 10[/tex]

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