Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
I assume the set A referred to among all the answer choices is actually supposed to be B, or the other way around so that
A = {1, 2, 3, {4, 5, 6, {7}}, 8}
A has 5 elements:
• 1
• 2
• 3
• {4, 5, 6, {7}}
• 8
Any non-empty subset of A is a set containing at least one of these elements.
The fourth element listed above, {4, 5, 6, {7}}, is itself a set with 4 elements (4, 5, 6, and yet another set {7} that contains just the 1 element 7).
Now,
• { } ⊆ A is true - the empty set is subset of every set
• {2, 3} ⊆ A is true - both 2 and 3 are elements of A, so {2, 3} is a subset of A
• {4, 5, 6, {7}} ⊆ A is false - the set {4, 5, 6, {7}} is an element of A, but not a subset
• {{2, 3}} ⊆ A is false - 2 and 3 are elements of A, but the set {2, 3} is not an element of A, so {{2, 3}} is not a subset
• {{4, 5, 6}, 8} ⊆ A is false - the set {4, 5, 6} is not an element of A
• {{4, 5, 6, {7}}} ⊆ A is true - the set {4, 5, 6, {7}} is an element of A
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.