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solve for x 7/8(-32-48x)+36=2/3(-33x-18)-10x

Sagot :

silirobert15

[tex]\frac{7}{8} (-32-48x) + 36 = \frac{2}{3} (-33x-18) -10x[/tex]

[tex]\frac{7}{8} (-32)+\frac{7}{8} (-48)+36=\frac{2}{3} (-33x)+\frac{2}{3} (-18)-10x[/tex]

[tex]-28-42+36=-22x-12-10x[/tex]

[tex]22x+10x=28+42-36-12[/tex]

[tex]32x=22[/tex]

[tex]x=\frac{22}{32} =\frac{11}{16} =0,6875[/tex]

Answer: x = 0.6875

Ok done. Thank to me :>

gwendoline05

Answer:

x = 2

Step-by-step explanation:

7/8 (-32-48x) + 36 = 2/3 (-33x-18) - 10x

Multiply,

7(-32-48x)/8 + 36 = 2(-33x-18)/3 -10x

Simpliy,

-336(3x+2) + 864 = -48(11x+6) - 240x

Expand,

-1008x + 192 = -768x - 288

Simplify,

-1008x = -768x -480

Simplify,

-240x = -480

Simplify,

x = -480/-240

Answer,

x = 2

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