Answer:
x = 1
Step-by-step explanation:
2x + 3 = 5
=> 2x = 5 - 3
=> 2x = 2
=> x = 2/2
=> x = 1
Answer:
[tex]\boxed{ \boxed{\huge\bf \; x = 1}}[/tex]
Step-by-step explanation:
[tex] \underline{\bf \: Given \: equation:-}[/tex]
[tex]2x + 3 = 5[/tex]
[tex]\underline{ \bf \: To \: Find :-}[/tex]
[tex]\rm Value\: of \: x [/tex]
[tex]\underline{ \bf \: Solution :-} [/tex]
[tex]\bf : \sf \longmapsto2x + 3 = 5[/tex]
[tex]\underline{\rm Subtract \: 3\: from\: both \; sides:}[/tex]
[tex]\bf : \sf \longmapsto2x + 3 - 3 = 5 - 3[/tex]
[tex]\underline{\rm On \: Simplification:}[/tex]
[tex]\bf : \sf \longmapsto2x + 0 = 2[/tex]
[tex]\bf : \sf \longmapsto2x = 0[/tex]
[tex]\underline{ \rm \: Divide \: both \: sides \: by \: 2 :} [/tex]
[tex]\bf : \sf \longmapsto \: \cfrac{2x}{2} = \cfrac{2}{ 2} [/tex]
[tex]\underline{\rm On \: Simplification:}[/tex]
[tex]\rm Cancel \: 2 \: and \: 2 \: of \: LHS \: and \: then \: Cancel \: 2 \: and \: 2 \: of \: RHS(Leave\: x \: of \: LHS)[/tex]
[tex] : \sf \longmapsto\cfrac{ \cancel2{x}}{\cancel2} = \cfrac{ \cancel2{}}{\cancel2}[/tex]
[tex] \underline{\rm \: On \: Cancelling,}[/tex]
[tex] : \sf \longmapsto1x = 1[/tex]
As [tex]\rm 1x = x [/tex]so,
[tex] : \sf \longmapsto \: x =\boxed{ 1}[/tex]
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