sclxlmasc
Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

I WILL MARK YOU AS BRAINLIST

Empirical formula for 160.87g Carbon, 4.38g Hydrogen, and 34.75g Oxygen.

Sagot :

rspill6

Answer:

C6H2O

Explanation:

See the attached table.

The masses of each element is converted to moles of that element by dividing the masses by that element's molar mass.  The resulting moles values are not even numbers, but we can multiply them by a constant factor that make them close to whole numbers.  Use 1/(moles O) [=0.46] as the converting factor for each mole result to yield, after rounding:

C    6

H    2

O    1

The empirical formula is C6H2O

View image rspill6
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.