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Answered

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Empirical formula for 160.87g Carbon, 4.38g Hydrogen, and 34.75g Oxygen.

Sagot :

rspill6

Answer:

C6H2O

Explanation:

See the attached table.

The masses of each element is converted to moles of that element by dividing the masses by that element's molar mass.  The resulting moles values are not even numbers, but we can multiply them by a constant factor that make them close to whole numbers.  Use 1/(moles O) [=0.46] as the converting factor for each mole result to yield, after rounding:

C    6

H    2

O    1

The empirical formula is C6H2O

View image rspill6
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