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Sagot :
Sure ,Let's find angle between forces
- Vectors be A and B and resultant be R
[tex]\\ \sf\longmapsto R^2=A^2+B^2+2ABcos\theta[/tex]
[tex]\\ \sf\longmapsto 27^2=20^2+40^2+2(20)(40)cos\theta[/tex]
[tex]\\ \sf\longmapsto 729=400+1600+1600cos\theta[/tex]
[tex]\\ \sf\longmapsto 729=2000+1600cos\theta[/tex]
[tex]\\ \sf\longmapsto 1600cos\theta=-271[/tex]
[tex]\\ \sf\longmapsto cos\theta=-0.169[/tex]
[tex]\\ \sf\longmapsto \theta=cos^{-1}(-0.169)[/tex]
[tex]\\ \sf\longmapsto \theta=80.2°[/tex]
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