grecon882
Answered

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In parallelogram EFGH, EJ = 6x + 3 and JG = 10x - 5 What is EG?
A: 15
B: 12
C: 25
D: 30​

In Parallelogram EFGH EJ 6x 3 And JG 10x 5 What Is EGA 15B 12C 25D 30 class=

Sagot :

mhanifa

Answer:

  • D. 30

Step-by-step explanation:

It seems J is the intersection of diagonals.

We know diagonals of the parallelogram bisect each other.

It gives us:

  • EG = EJ + JG and
  • EJ  = JG

Substitute and solve for x:

  • 6x + 3 = 10x - 5
  • 10x - 6x = 3 + 5
  • 4x = 8
  • x = 2

Find the value of EJ:

  • EJ = 6*2 + 3 = 15

Find the value of EG:

  • EG = 2*EJ = 2*15 = 30

Correct choice is D

Answer:

30

Step-by-step explanation:

We know that

Opposite sides of a parallelogram are equal. I am assuming J as the diagonal.

EJ = JG

=> 6x + 3 = 10x - 5

=> 6x - 10x = -5 - 3

=> -4x = -8

=> x = -8/-4

=> x = 2

Now,

EG = 2EJ

EG = 2(6 × 2 + 3)

EG = 2(12 + 5)

EG = 2(15)

EG = 30

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