At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

y-1=-1/2(x-2)
I need this in standard form plz

Sagot :

Answer:

x+2y=4

Step-by-step explanation:

Hi there!

We are given the equation y-1=-1/2(x-2), and we want to write it in standard form

Standard form is ax+by=c, where a, b, and c are free integer coefficients, but a and b cannot be zero and a cannot be negative

The equation is currently in slope-point form, which is [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point belonging to the line

In order to get from slope-point form to standard form, we need to first simplify the equation into slope-intercept form and then convert to standard form.

Slope-intercept form is y=mx+b, where m is the slope and b is the y intercept.

So, let's convert  from slope-point form into slope-intercept form

Start by distributing -1/2 to each number on the right side

y-1=-1/2*x + -1/2*-2

y-1=-1/2x+1

Now add 1 to both sides

y=-1/2x+2

The equation is now in slope-intercept form

In standard form, x and y are on the same side, so let's add -1/2x to both sides in order to move it.

y=-1/2x+2

+1/2x +1/2x

______________

1/2x+y=2

We're almost done; remember that a, the coefficient in front of x CANNOT be negative

So let's multiply both sides by 2 in order to clear the fraction

2(1/2x+y)=2(2)

multiply

x+2y=4

Hope this helps!

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.