rebendrabasnet864
Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A box of mass 15 kg placed on horizontal 4 floor is pulled by a horizontal force. What will be the work done by the force if the coefficient of sliding friction between the box and the surface of the floor is 0.3 and body moved at unit distance.​

Sagot :

LammettHash

The net force on the box perpendicular to the floor is

∑ F[perp] = F[normal] - mg = 0

where mg is the weight of the box. Then

F[normal] = mg = 147 N

so that

F[friction] = 0.3 F[normal] = 44.1 N

The net force parallel to the floor is

∑ F[para] = F[applied] - F[friction] = ma

where a is the acceleration of the box. Then

F[applied] = (15 kg) a + 44.1 N

Then the work done by the applied force is

W[applied] = ((15 kg) a + 44.1 N) (1 m) = (15a + 44.1) J

We can't find the exact amount of work without any more information. If the box is pulled with constant speed, then a = 0 so the work would be 44.1 J.

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.