A973
Answered

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Simplify.
1: if y>0
2: if y<0
[tex]1): -15\sqrt{y^2}\\2): -\sqrt{16y^2}[/tex]

Sagot :

LammettHash

In general, √(y²) = |y|, since y can be positive or negative and y² would have the same value either way.

So,

1) if y > 0, then |y| = y, and

-15√(y²) = -15 |y| = -15y

2) if y < 0, then |y| = -y, and

-√(16y²) = -|4y| = -|4| |y| = -4 (-y) = 4y

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