Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Rob walks up to a tank of water that can hold 85 gallons. When it is active a drain
empties water from the tank at a constant rate. When Bob first sees the tank it
contains 30 gallons of water. 5 minutes later, the tank contains 15 gallons of water.

Sagot :

mathstudent55

Answer:

rate of change: 3 gal/min

minutes to empty: 5 minutes

minutes before Bob arrived that tank was full: 18 1/3 minutes

Step-by-step explanation:

When Bob first saw it, the tank contained 30 gal. 5 minutes later it contained 15 gal.

Difference in gallons: 30 - 15 = 15

Difference in time: 5 minutes

Rate of draining: 15 gal / 5 minutes = 3 gal/minute

It drained 15 gallons in 5 minutes. It has 15 gallons now, so it will take 5 minutes to empty out.

The total capacity is 85 gallons. When Bob saw it, it only had 30 gallons.

85 gal - 30 gal = 55 gal

It had emptied 55 gallons before Bob saw it.

emptying rate = volume/time

time = volume/rate

time = 55 gal / (3 gal/min)

time = 55/3 minutes

time = 18 1/3 minutes

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.