Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A merry-go-round rotates with a centripetal acceleration of 21 m/s2. If the
outer horses are 10 m from the center of the ride, what is their velocity?
O A. 17.1 m/s
O B. 16.8 m/s
C. 14.5 m/s
D. 15.2 m/s

Sagot :

Lanuel

The velocity of this merry-go-round that rotates around a center is equal to: C. 14.5 m/s.

Given the following data:

  • Radius = 10 meters
  • Centripetal acceleration = 21 [tex]m/s^2[/tex]

To determine the velocity of this merry-go-round that rotates around a center:

The formula for centripetal acceleration.

Mathematically, the centripetal acceleration of an object is given by the formula:

[tex]A_c = \frac{V^2}{r}[/tex]

Where:

  • [tex]A_c[/tex] is the centripetal acceleration.
  • r is the radius of a circular track.
  • V is the velocity of an object.

Making V the subject of formula, we have:

[tex]V=\sqrt{A_cr}[/tex]

Substituting the given parameters into the formula, we have;

[tex]V=\sqrt{21 \times 10}\\\\V=\sqrt{210}[/tex]

V = 14.5 m/s.

Read more on centripetal acceleration here: https://brainly.com/question/2788500

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.