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Sagot :
The motion of the ball dropped from height is a free fall motion due to
gravitational acceleration.
Correct response;
- The equation that models the height is; y = -16·x²
Method for arriving at the above equation;
Given values;
[tex]\begin{tabular}{|c|c|}Height (feet)&Time (s)\\200&0\\184&1\\136&2\end{array}\right][/tex]
Required:
To select the equation that models the height, y, of the ball x seconds after
its dropped;
Solution:
From the above table, we have that the first difference is not a constant
The second difference is = 48 - 16 = 32
Taking the second difference as a constant, we have the following
quadratic sequence;
y = a·x² + b·x + c
Where;
x = The time in seconds
y = The height after x seconds
- At x = 0, we have;
200 = a·0² + b × 0 + c
Therefore;
c = 0
- At x = 1, we have;
184 = a × 1² + b × 1 + 200
184 = a + b + 200
a + b = -16
a = -16 - b
- At x = 2, we have;
136 = a × 2² + b × 2 + 200
136 = 4·a + 2·b + 200
-64 = 4·a + 2×b
Therefore;
-64 = 4 × (-16 - b) + 2×b
-64 = -64 - 4·b + 2×b
b = 0
a + b = -16
Therefore;
a + 0 = -16
a = -16
The equation that models the height is; y = -16·x²
Learn more about quadratic function here;
https://brainly.com/question/2293136
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