Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

2NH3 + MgSO4 + 2H20-→ Mg(OH)2 + (NH4)2SO4
Using the chemical equation above answer the following questions.
If I have 4.6 moles of MgSO, and 5.4 moles of NH3 which one is the limiting
reactant? You must show your work for credit.

Sagot :

niki808
Chemistry msg for 78 mgSO 5.4 answer is NH3
khuranashilpa76

The limiting reactant is NH3

What is a limiting reagent?

The limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops. From the reaction stoichiometry, the exact amount of reactant needed to react with another element can be calculated.

2NH3 + MgSO4 + 2H20-→ Mg(OH)2 + (NH4)2SO4

For limiting reagent:-

 MgSO4= moles / stoichiometry coefficient

                ⇒ 4.6/1

NH3 =  moles / stoichiometry coefficient

           ⇒ 5.4/2

             ⇒ 2.7

HENCE, the limiting reagent is - NH3.

Learn more about limiting reagents here:-https://brainly.com/question/26905271

#SPJ2

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.