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2NH3 + MgSO4 + 2H20-→ Mg(OH)2 + (NH4)2SO4
Using the chemical equation above answer the following questions.
If I have 4.6 moles of MgSO, and 5.4 moles of NH3 which one is the limiting
reactant? You must show your work for credit.

Sagot :

niki808
Chemistry msg for 78 mgSO 5.4 answer is NH3
khuranashilpa76

The limiting reactant is NH3

What is a limiting reagent?

The limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops. From the reaction stoichiometry, the exact amount of reactant needed to react with another element can be calculated.

2NH3 + MgSO4 + 2H20-→ Mg(OH)2 + (NH4)2SO4

For limiting reagent:-

 MgSO4= moles / stoichiometry coefficient

                ⇒ 4.6/1

NH3 =  moles / stoichiometry coefficient

           ⇒ 5.4/2

             ⇒ 2.7

HENCE, the limiting reagent is - NH3.

Learn more about limiting reagents here:-https://brainly.com/question/26905271

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