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Sagot :
14 of the machine that cost $150 was sold and 8 of the machine that cost $225 was sold.
To solve this problem, we would write a system of linear equations.
- Let x represent the machine that cost $150
- Let y represent the machine that cost $225
We can proceed to write our equations now.
[tex]x + y = 22...equation(i)\\150x + 225y = 3900...equation(ii)[/tex]
From equation 1
[tex]x+ y = 22\\x = 22 - y...equation (iii)[/tex]
The Value of Y
put equation (iii) into (ii)
[tex]150x + 225y =3900\\x = 22-y\\150(22-y)+225y=3900\\3300-150y+225y=3900\\3300+75y=3900\\75y=3900-3300\\75y=600\\75y/75=600/75\\y=8[/tex]
The Value of X
Since we know the number of y, we can simply substitute it into equation (i) and solve.
[tex]x + y = 22\\x + 8 = 22\\x = 22-8\\x = 14[/tex]
From the calculations above, 14 of the machine that cost $150 was sold and 8 of the machine that cost $255 was sold.
Learn more about system of equations here;
https://brainly.com/question/13729904
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