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The motion of a particle is described by the position function s(t) = 2t - 15t +33t+17,t>0 , where is measured in seconds and s(t) in metres.
a) When is the particle at rest?
b) When is the velocity positive?
c) Draw a diagram to illustrate the motion of the particle in the first 10 seconds.
d) Find the total distance traveled in the first 10 seconds.

Sagot :

onyebuchinnaji

The time when the particle is at rest is at 1.63 s or 3.36 s.

The velocity is positive at when the time of motion is at [tex]0<t<1.63 \ s \ \ or \ \ t> 3.36 \ s[/tex].

The total distance traveled in the first 10 seconds is 847 m.

When is a particle at rest?

  • A particle is at rest when the initial velocity of the particle is zero.

The time when the particle is at rest is calculated as follows;

s(t) = 2t³ - 15t² + 33t + 17

[tex]v = \frac{ds}{dt} = 6t^2 -30t + 33\\\\at \ rest, \ v = 0\\\\6t^2 - 30t + 33 = 0\\\\6(t- \frac{5}{2} )^2- \frac{9}{2} = 0\\\\t = 1.63\ s \ \ or \ 3.36 \ s[/tex]

The velocity is positive at when the time of motion is as follows;

[tex]0<t<1.63 \ s \ \ or \ \ t> 3.36 \ s[/tex].

The total distance traveled in the first 10 seconds is calculated as follows;

[tex]2(10)^3 - 15(10)^2 + 33(10) + 17 = 847 \ m[/tex]

Learn more about motion of particles here: https://brainly.com/question/11066673

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