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What is the average oxidation state of tungsten in sodium phosphotungstate, Na3PW12O40?
(A) +6.00
(B) +6.17
(C) +6.42
(D) +6.67

Sagot :

Eduard22sly

The average oxidation state of tungsten, W in Na₃PW₁₂O₄₀ is +6.67

The correct answer to the question is Option D. +6.67

Oxidation number of individual elements in Na₃PW₁₂O₄₀  

  • Sodium (Na) = +1
  • Phosphorus (P) = –3
  • Oxygen (O) = –2
  • Tungsten (W) =?

The oxidation number of tungsten, W in Na₃PW₁₂O₄₀ can be obtained as follow:

Na₃PW₁₂O₄₀ = 0 (group state)

3Na + P + 12W + 40O = 0

3(1) + (–3) + 12W + 40(–2) = 0

3 – 3 + 12W – 80 = 0

12W – 80 = 0

Collect like terms

12W = 0 + 80

12W = 80

Divide both side by 12

W = 80 / 12

W = +6.67

Thus, the oxidation number of tungsten, W in Na₃PW₁₂O₄₀ is +6.67

Learn more about oxidation number:

https://brainly.com/question/2510539

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