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Sagot :
Answer:
Factor by Grouping
2[tex]x^{3}[/tex] + 5[tex]x^{2}[/tex] - 8x - 20
2[tex]x^{3}[/tex] + 5[tex]x^{2}[/tex]
[tex]x^{2}[/tex] (2x + 5)
-8x - 20
-4 (2x + 5)
(2x + 5) ([tex]x^{2}[/tex] - 4)
(2x + 5) (x - 2) (x + 2)
Solution:
- 2x³ + 5x² - 8x - 20
Putting the terms, which have something in common, in brackets:
- (2x³ + 5x²) - (8x - 20)
Factor them by taking the common terms outside the bracket.
- => x²(2x + 5) - 4(2x + 5)
Factor by taking the common expression out of the brackets:
- => (2x + 5)(x² - 4)
The multiplier (x² - 4) is in squared form.
Square root the multiplier of (2x + 5)(x² - 4), aka (x² - 4):
- => (2x + 5)(x - 2)(x + 2)
The factorized form is (2x + 5)(x - 2)(x + 2).
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