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A race car has a velocity of 382 km/h to the right. If the car’s mass is 705 kg and the driver’s mass is 65 kg, what force is needed to bring the car and driver to a stop in 12.0 s? What is the car’s stopping distance?

Sagot :

Answer:

Given: Vi = 382 km/h, Vf = 0 km/h, Mc = 705 kg, Md = 65 kg, Δt = 12

Required: Δx

F = Δp / Δt

  = [tex]\frac{(Mc+Md)Vf-(Mc+Md)Vi}{t} \\\\= 6.81 * 10x^{3} N [left]\\\\x=\frac{1}{2} (Vi+Vf)\\ \\ = 637m[right][/tex]

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