sierrajohnson75
Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Can someone please help me with questions 13 and 14?

Can Someone Please Help Me With Questions 13 And 14 class=

Sagot :

Answer:   #13 is 26,  #14 is 18

Step-by-step explanation:

13.

The whole line has length [tex]8x - 20[/tex], and [tex]AB = BC = 3x - 1[/tex]. Thus

[tex](3x -1) + (3x-1)=8x-20\\6x - 2 = 8x - 20\\18 = 2x\\x = 9[/tex]

Now we plug this into [tex]3x - 1[/tex] (since this is the length of BC) to get

[tex]3(9) - 1 = \boxed{26}[/tex].

14.

We can use the fact that CG = GD, so [tex]5x - 1 = 7x - 13[/tex] and thus [tex]x = 6[/tex].

We know [tex]EG = EF - GF[/tex], so

[tex]EG = (6x - 4) - 13 = (6 \cdot 6 - 4) - 14 = \boxed{18}.[/tex]

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.