sierrajohnson75
Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Can someone please help me with questions 13 and 14?

Can Someone Please Help Me With Questions 13 And 14 class=

Sagot :

Answer:   #13 is 26,  #14 is 18

Step-by-step explanation:

13.

The whole line has length [tex]8x - 20[/tex], and [tex]AB = BC = 3x - 1[/tex]. Thus

[tex](3x -1) + (3x-1)=8x-20\\6x - 2 = 8x - 20\\18 = 2x\\x = 9[/tex]

Now we plug this into [tex]3x - 1[/tex] (since this is the length of BC) to get

[tex]3(9) - 1 = \boxed{26}[/tex].

14.

We can use the fact that CG = GD, so [tex]5x - 1 = 7x - 13[/tex] and thus [tex]x = 6[/tex].

We know [tex]EG = EF - GF[/tex], so

[tex]EG = (6x - 4) - 13 = (6 \cdot 6 - 4) - 14 = \boxed{18}.[/tex]

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.