Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Find the vertex of the parabola y = -5x² - 6x + 15/2

Sagot :

[tex]\\ \sf\longmapsto y=-5x^2-6x+15/2[/tex]

[tex]\\ \sf\longmapsto -5x^2-6x-y+15/2=0[/tex]

  • Multiply 2 with each term

[tex]\\ \sf\longmapsto -10x^2-12x-2y+15=0[/tex]

  • Convert to vertex form

[tex]\\ \sf\longmapsto y=-5(x^2+\dfrac{6}{5}x+\dfrac{9}{25})+\dfrac{93}{10}[/tex]

[tex]\\ \sf\longmapsto y=-5(x^2+2\dfrac{3}{5}x+(\dfrac{3}{5})^2)+\dfrac{93}{10}[/tex]

[tex]\\ \sf\longmapsto y=-5(x+\dfrac{3}{5})^2+\dfrac{93}{10}[/tex]

Compare to vertex form of parabola

[tex]\boxed{\sf y=a(x-h)^2+k}[/tex]

Now

  • h=-3/5
  • k=93/10
mhanifa

Answer:

  • (- 0.6, 9.3)

Step-by-step explanation:

Given parabola:

  • y = -5x² - 6x + 15/2

The vertex is determined by x = - b/2a:

  • x = - (-6)/(2*(-5)) = -0.6

Find y- coordinate of vertex:

  • y = - 5(0.6)² - 6(- 0.6) + 15/2 = 9.3
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.