Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
[tex]\\ \sf\longmapsto y=-5x^2-6x+15/2[/tex]
[tex]\\ \sf\longmapsto -5x^2-6x-y+15/2=0[/tex]
- Multiply 2 with each term
[tex]\\ \sf\longmapsto -10x^2-12x-2y+15=0[/tex]
- Convert to vertex form
[tex]\\ \sf\longmapsto y=-5(x^2+\dfrac{6}{5}x+\dfrac{9}{25})+\dfrac{93}{10}[/tex]
[tex]\\ \sf\longmapsto y=-5(x^2+2\dfrac{3}{5}x+(\dfrac{3}{5})^2)+\dfrac{93}{10}[/tex]
[tex]\\ \sf\longmapsto y=-5(x+\dfrac{3}{5})^2+\dfrac{93}{10}[/tex]
Compare to vertex form of parabola
[tex]\boxed{\sf y=a(x-h)^2+k}[/tex]
Now
- h=-3/5
- k=93/10
Answer:
- (- 0.6, 9.3)
Step-by-step explanation:
Given parabola:
- y = -5x² - 6x + 15/2
The vertex is determined by x = - b/2a:
- x = - (-6)/(2*(-5)) = -0.6
Find y- coordinate of vertex:
- y = - 5(0.6)² - 6(- 0.6) + 15/2 = 9.3
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.