Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Find the vertex of the parabola y = -5x² - 6x + 15/2

Sagot :

[tex]\\ \sf\longmapsto y=-5x^2-6x+15/2[/tex]

[tex]\\ \sf\longmapsto -5x^2-6x-y+15/2=0[/tex]

  • Multiply 2 with each term

[tex]\\ \sf\longmapsto -10x^2-12x-2y+15=0[/tex]

  • Convert to vertex form

[tex]\\ \sf\longmapsto y=-5(x^2+\dfrac{6}{5}x+\dfrac{9}{25})+\dfrac{93}{10}[/tex]

[tex]\\ \sf\longmapsto y=-5(x^2+2\dfrac{3}{5}x+(\dfrac{3}{5})^2)+\dfrac{93}{10}[/tex]

[tex]\\ \sf\longmapsto y=-5(x+\dfrac{3}{5})^2+\dfrac{93}{10}[/tex]

Compare to vertex form of parabola

[tex]\boxed{\sf y=a(x-h)^2+k}[/tex]

Now

  • h=-3/5
  • k=93/10
mhanifa

Answer:

  • (- 0.6, 9.3)

Step-by-step explanation:

Given parabola:

  • y = -5x² - 6x + 15/2

The vertex is determined by x = - b/2a:

  • x = - (-6)/(2*(-5)) = -0.6

Find y- coordinate of vertex:

  • y = - 5(0.6)² - 6(- 0.6) + 15/2 = 9.3
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.