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In the accompanying diagram of circle O, point O
is the origin, YO = 1, J0 = 1, and TOY is a diameter. If the coordinates of point J are (sqrt2/2 , sqrt2/2), how many degrees are in the m

In The Accompanying Diagram Of Circle O Point O Is The Origin YO 1 J0 1 And TOY Is A Diameter If The Coordinates Of Point J Are Sqrt22 Sqrt22 How Many Degrees A class=

Sagot :

The number of degrees in the first quadrant is 45 degrees.

Coordinates of a circle

The formula for calculating the angle in the first quadrant If the coordinates of point J are [tex](\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})[/tex]

[tex]tan \theta = \frac{y}{x}\\tan \theta =\frac{\frac{\sqrt{2}}{2} }{\frac{\sqrt{2}}{2} }\\tan \theta =1\\\theta = tan^{-1}1\\\theta = 45^0[/tex]

From the calculation above the number of degrees in the first quadrant is 45 degrees.

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