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An arrow is shot parallel to horizontal from a height of 1.4 meters. It has a velocity of 49 m/s.

a. How long will it take to hit the ground?
b. what horizontal distance will the arrow travel

i need the answer for both please help. i need to show
work

Sagot :

onyebuchinnaji

The time taken for the arrow to hit the ground is 0.53 s.

The horizontal distance traveled by the arrow is 25.97 m.

The given parameters:

  • Initial horizontal velocity, [tex]v_x[/tex] = 49 m/s
  • Initial vertical velocity, [tex]v_y[/tex] = 0

What is time of motion?

  • This is the time taken for a projectile to land on the plane of projection.

The time of motion is calculated as follows;

[tex]h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 1.4}{9.8} }\\\\t = 0.53 \ s[/tex]

The horizontal distance traveled by the arrow is calculated as follows;

[tex]X = v_x t\\\\X = (49\ m/s) \times (0.53 \ s)\\\\X = 25.97 \ m[/tex]

Learn more about time of motion here: https://brainly.com/question/2364404

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