Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The limiting reagent and the number of S'mores produced for each of the reactions is given below:
Reaction 1. The limiting reagent is Cp; 1.6 S'mores are produced.
Reaction 2. The limiting reagent is M; 2 S'mores are produced.
Reaction 3. The limiting reagent is Gc; 2.5 S'mores are produced.
Reaction 4. The limiting reagent is M; 1 S'more is produced.
Stoichoimetry
- Stoichiometry is the process of measuring quantitatively the mass and quantity relationships among reactants and products in a given reaction.
The equation of the reaction shows the stoichiometry between reactants and products.
For the given reaction, the equation of reaction is as follows:
1M + 2Gc + 3Cp ----> 1Gc2MCp3
where:
- Gc = Graham Cracker
- M = Marshmallow
- Cp = Chocolate pieces
- S’more = Gc2MCp3
From the equation of reaction:
- 1 marshmallow, 2 Graham cracker and 3 chocolate pieces are required to make 1 S'more
Calculating the number of S'mores and the limiting reactant of the given reaction
The stoichiometric equation is: 2Gc + 1M + 3Cp ----> 1Gc2MCp3
The ratio of Gc to M to Cp is 2 : 1 : 3
Reaction 1. 4 Gc + 2M + 5 Cp
The ratio of Gc to M to Cp in the reaction above is 2 : 1 : 2.5
- Therefore the limiting reagent is Cp
3 Cp makes 1 S'more
5 Cp will make 5 * 1/3 S'more = 1.6 S'mores
- Therefore, 1.6 S'mores are produced.
Reaction 2. 6 Gc + 2M + 9 Cp
The ratio of Gc to M to Cp in the reaction above is 3 : 1 : 4.5
- Therefore the limiting reagent is M
1 M makes 1 S'more
2 Cp will make 2 * 1/1 S'more = 2 S'mores
- Therefore, 2 S'mores are produced.
Reaction 3. 5 Gc + 3M + 9 Cp
The ratio of Gc to M to Cp in the reaction above is 1.6 : 1 : 3
- Therefore the limiting reagent is Gc
2 Gc makes 1 S'more
5 Gc will make 5 * 1/2 S'more = 2.5 S'mores
- Therefore, 2.5 S'mores are produced.
Reaction 4. 7 Gc + 1M + 6 Cp
The ratio of Gc to M to Cp in the reaction above is 7 : 1 : 6
Therefore the limiting reagent is M
1 M makes 1 S'more
- Therefore, 1 S'more is produced.
The limiting reagent and the number of S'mores produced for each of the reactions is given below:
1. The limiting reagent is Cp; 1.6 S'mores are produced.
2. The limiting reagent is M; 2 S'mores are produced.
3. The limiting reagent is Gc; 2.5 S'mores are produced.
4. The limiting reagent is M; 1 S'more is produced.
Learn more about Stoichiometry and limiting reagents at: https://brainly.com/question/14222359
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.