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Find the applied voltage of a circuit that draws 0.2 amperes through a 4800-ohmresistance

Sagot :

  • Current=I=0.2A
  • Resistance=R=4800ohm

  • Voltage =V

Using ohms law.

[tex]\\ \sf\longmapsto \dfrac{V}{I}=R[/tex]

[tex]\\ \sf\longmapsto V=IR[/tex]

[tex]\\ \sf\longmapsto V=4800(0.2)[/tex]

[tex]\\ \sf\longmapsto V=960V[/tex]

[tex]\\ \sf\longmapsto V=0.96KV[/tex]

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