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Sagot :
Answer:
sin 40 = n sin 26 snell's law for incoming ray in air
n = sin 40 / sin 26 = 1.47
The index of refraction of the transparent material is 1.47. The value of the refractive index depends upon the material.
What is an index of refraction?
The refractive index of a substance also known as the refraction index or index of refraction is a dimensionless quantity that specifies how quickly light passes through an object.
The given data in the problem is;
The wavelength of a ray of light in a vacuum is, [tex]\lambda = 550 \ nm[/tex]
The incoming ray makes an angle, [tex]\rm \theta = 40^0[/tex]
the refracted ray makes an angle,[tex]\rm \theta_R= 26.0^0[/tex]
The index of refraction of the transparent material is,n
The index of refraction is found as;
[tex]\rm n= \frac{sin 40^0}{sin 26^0} \\\\ n= 1.47[/tex]
Hence the index of refraction of this medium will be 1.47.
To learn more about the index of refraction refer to the link;
https://brainly.com/question/23750645
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