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the extension-load graph for a spring is shown. the unstretched length of the spring is 17.0 cm. when an object is hung from the spring, the length of the spring is 19.2. what is the weight of the object?

Sagot :

onyebuchinnaji

The weight of the object hung from the spring is 6.27 N.

Hooke's law;

  • Hooke's law states that the load applied to an elastic material is directly proportional to the extension of the material provided elastic limit is not exceeded.

F = Kx

[tex]k = \frac{F}{x} \\\\k = F (\frac{1}{x} )\\\\k = \frac{1}{slope}[/tex]

From the graph, we can use the following points to determine the slope of the graph;

(2, 0.8) and (4, 1.5)

[tex]k = \frac{1.5 - 0.8}{4-2} \\\\k = 0.35 \\\\\frac{1}{k} = \frac{1}{0.35} = 2.85 \ N/cm[/tex]

The extension of the spring is calculated as follows;

x = 19.2 cm - 17.0 cm = 2.2 cm

The weight of the object hung from the spring is calculated as follows;

F = kx

F = 2.85 x 2.2

F = 6.27 N

Learn more about Hooke's law here: https://brainly.com/question/2648431

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